Question

There are two traffic lights on the route from home to work for particular individual. The probability that the individual will need to stop at the first light is 0.35 and the probability that the individual will need t stop at the second light is 0.42 . It is known that the probability that the individual will need to stop at both lights is 0.15 . The probabilities that the-individul witl need to stop the firstand the secontlights are independent. a. What is the probability that the individual will need to stop at least one light? 0.35⋅0.42=0.147

Answer 1

The probability of stopping at least one traffic light is 0.853.

Step-by-step explanation:

The probability that the individual will need to stop at the first light is 0.35, and the probability that the individual will need to stop at the second light is 0.42. Since the probabilities of stopping at each light are independent, we can multiply the probabilities together to find the probability of stopping at both lights:

Probability of stopping at both lights = 0.35 * 0.42 = 0.147

To find the probability of stopping at least one light, we need to subtract the probability of not stopping at either light from 1:

Probability of stopping at least one light = 1 - Probability of not stopping at either light

The probability of not stopping at either light can be found by subtracting the probability of stopping at both lights from 1:

Probability of not stopping at either light = 1 - 0.147 = 0.853

Therefore, the probability of stopping at least one light is 0.853.