Question

All that is left in a packet of candy are 7 reds, 2 greens, and 3 blues. (a) What is the probability that a random drawing yields a green followed by a red candy? (Assume that the selection is done with replacement) ?

a) Yes
b) No

Answer 1

The probability of drawing a green candy followed by a red candy from the packet is 7/72.

Step-by-step explanation:

To find the probability of drawing a green candy followed by a red candy from the packet, we need to calculate the probability of each event separately and then multiply them together.

1. The probability of drawing a green candy is 2/12, since there are 2 green candies out of a total of 12 candies.
2. The probability of drawing a red candy is 7/12, since there are 7 red candies left out of the 12 candies.

To find the overall probability, we multiply these two probabilities:

P(Green followed by Red) = (2/12) * (7/12) = 14/144 = 7/72.