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From an urn containing 9 red balls and 5 green balls, six balls are taken without replacement. Determine the probability that 6 of the balls are red and 3 of them are green.

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Final answer:

To determine the probability of selecting 6 red balls and 3 green balls from the urn, use the concept of combinations.

Step-by-step explanation:

To determine the probability of selecting 6 red balls and 3 green balls from an urn containing 9 red balls and 5 green balls without replacement, we need to use the concept of combinations.

The total number of ways to select 6 balls out of 14 (9 red + 5 green) is given by the combination formula, C(14, 6).

The number of ways to select 6 red balls out of 9 is given by the combination formula, C(9, 6).

The number of ways to select 3 green balls out of 5 is given by the combination formula, C(5, 3).

The probability of selecting 6 red balls and 3 green balls is then P(6 red and 3 green) = (C(9, 6) * C(5, 3)) / C(14, 6).

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