Question

Assuming the population has an approximate normal distribution, if a sample size n=12 has a sample mean x¯=44 with a sample standard deviation s=2, find the margin of error at a 98% confidence level. Round the answer to two decimal places.

Answer 1

To find the margin of error at a 98% confidence level, you can use the formula Margin of Error = critical value * standard deviation / sqrt(sample size). In this case, the margin of error is 1.35.

Step-by-step explanation:

To find the margin of error at a 98% confidence level, we can use the formula:

Margin of Error = critical value * standard deviation / sqrt(sample size)

First, we need to find the critical value from the z-table. Since we are looking for a 98% confidence level, we can use a z-value of 2.33.

Next, we can substitute the values into the formula:

Margin of Error = 2.33 * 2 / sqrt(12) = 1.35 (rounded to two decimal places)

So, the margin of error at a 98% confidence level is 1.35.