Final answer:
To find the probability that at least 65 visitors had a recorded entry through the Beaver Meadows park entrance, we can use the normal approximation of the binomial distribution. Calculating the mean and standard deviation, we can then use the z-score formula to find the probability.
Step-by-step explanation:
To find the probability that at least 65 visitors had a recorded entry through the Beaver Meadows park entrance, we can use the normal approximation of the binomial distribution. We can assume that the number of visitors entering through the Beaver Meadows park entrance follows a normal distribution with a mean of np and a standard deviation of sqrt(npq), where n is the sample size, p is the probability of success, and q is the probability of failure. In this case, n = 175 and p = 0.467.
First, we calculate the mean (np) and standard deviation (sqrt(npq)):
- Mean = 175 * 0.467 = 81.725
- Standard Deviation = sqrt(175 * 0.467 * (1 - 0.467)) = 7.703
Next, we can use the z-score formula to calculate the probability:
P(X >= 65) = 1 - P(X < 65) = 1 - P(Z < (65 - 81.725)/7.703)
Using a standard normal distribution table or a calculator, we can find the probability associated with the calculated z-score and subtract it from 1 to find the final probability. The result is the probability that at least 65 visitors had a recorded entry through the Beaver Meadows park entrance.