Question

Find CDF of f(x): 1/8(x+1) when 2

Answer 1

To find the CDF of f(x) = 1/8(x+1) when x > 2, integrate the function from 2 to x and evaluate it at x.

Step-by-step explanation:

To find the CDF of f(x) = 1/8(x+1) when x > 2, we need to integrate the function from 2 to x and then evaluate it at x:

CDF(x) = ∫(2 to x) [1/8(t+1)] dt

Simplifying the integral, we get CDF(x) = (1/8) * [((x^2)/2 + x) - ((2^2)/2 + 2)]

Therefore, the CDF of f(x) is CDF(x) = (1/8) * [(x^2)/2 + x - 1]