Final answer:
Using the given sample statistics, the normal sampling distribution can be used because both np and nq are greater than 5. The null and alternative hypotheses are H₀: p = 0.24 and H₁: p ≠ 0.24 respectively. The critical z-values for α = 0.05 in a two-tailed test are ±1.96.
Step-by-step explanation:
To determine if we can use the normal sampling distribution for testing the claim about the population proportion, we should check if np and nq are both greater than or equal to 5.
Given the sample statistics, with p = 0.22 and n = 200, we calculate np = 0.22 * 200 = 44 and nq = (1-0.22) * 200 = 0.78 * 200 = 156. Since both values are greater than 5, the normal sampling distribution can be used.
The null and alternative hypotheses for testing the claim that p = 0.24 at the 0.05 level of significance are as follows:
For a two-tailed test using the normal distribution, we need to calculate the critical value(s). Since the level of significance is α = 0.05, the critical z-values will be ±1.96.