Question

A young bull frog, Jumper, is being genetically evaluated for his jumping ability. The information you have for analysis includes his jumping records, lots of paternal half-sib data, a couple of maternal half-sib records and limited progeny data. All of this data is combined into the following selection index:

I=b₁x₁ +b₂x₂ +b₃x₃ +b₄x₄
​− or-
EBV=b₁P_IND +b₂ P_PHS+b₃P_MHS+b₄ P_PROG
​ Weighting factors calculated from simultaneous equations:
b₁ =.169
b₂ =.500
b₃ =.075
b₄ =.624
​Given the following performance data (deviations from CG means)
P_IND =+14 cm
P_PHS =+4 cm
P_MHS =+8 cm
​P_PROG =+10 and accuracy of prediction calculated as: 1. Calculate Jumper's EBV for jumping ability 1. Calculate Jumper's EPD for jumping ability 1. Calculate the accuracy of prediction

Answer 1

Jumper's EBV for jumping ability is 11.206.

Step-by-step explanation:

To calculate Jumper's EBV for jumping ability, we need to plug in the respective values for each performance data into the formula EBV = b₁P_IND + b₂P_PHS + b₃P_MHS + b₄P_PROG. Given b₁ = .169, b₂ = .500, b₃ = .075, and b₄ = .624, and the performance data values P_IND = +14 cm, P_PHS = +4 cm, P_MHS = +8 cm, and P_PROG = +10, we can calculate the EBV for Jumper's jumping ability as follows:

EBV = (.169 * 14) + (.500 * 4) + (.075 * 8) + (.624 * 10) = 2.366 + 2.000 + 0.600 + 6.240 = 11.206