Final answer:
In (a), the data type is stated for each item. In (b), the probabilities of 0 days and 3 or more days with severe snow in a given week are calculated.
Step-by-step explanation:
(a) For each of the following data collected:
- (i) Number of days having severe snow: Numerical, Discrete
- (ii) The intensity of snowfall (i.e. light, moderate, heavy): Categorical, Nominal
- (iii) The lowest temperature (in∘C) in each day: Numerical, Continuous
(b) Based on the past records, the probability of a day having severe snow is 0.06. Given that a day having severe snow is independent to the other days, the probability that in a given week:
- (i) there will be 0 day with severe snow: (0.94)^7 = 0.5184
- (ii) there will be 3 or more days with severe snow: 1 - P(no days or 1 or 2 days with severe snow) = 1 - [(0.94)^7 + 7C1 * (0.06) * (0.94)^6 + 7C2 * (0.06)^2 * (0.94)^5] = 0.9633