Question

A box contains 13 balls: 8 blue, 4 red, and 1 green. Two balls

are selected without replacement. Find: P(both balls are blue) =
______________

Answer 1

The probability that both balls drawn are blue is 7/39.

Step-by-step explanation:

To find the probability that both balls selected are blue, we need to calculate the probability of drawing a blue ball on the first draw and then a blue ball on the second draw.

There are 8 blue balls out of a total of 13 balls in the box, so the probability of selecting a blue ball on the first draw is 8/13.

After the first ball is selected, there are now 12 balls left in the box, including 7 blue balls. So the probability of selecting a blue ball on the second draw, given that the first ball was blue and not replaced, is 7/12.

To find the probability of both events happening, we multiply the probabilities together: (8/13) * (7/12) = 56/156 = 7/39.