Question

Let x be a continuous random variable that follows a distribution skewed to the left with" = 89 and = 22. Assumin n/N< 0.05.

find the probability that the sample mean, for a random sample of 66 taken from this population will be at
(a) less than 84.8
(b). greater than 886.

Answer 1

To find the probability that the sample mean, for a random sample of 66 taken from a population with a left-skewed distribution with mean (mu) = 89 and standard deviation (sigma) = 22, is less than 84.8 or greater than 886, you can use the Central Limit Theorem and standardize the values.

Step-by-step explanation:

To find the probability that the sample mean, for a random sample of 66 taken from a population with a left-skewed distribution with mean (mu) = 89 and standard deviation (sigma) = 22, is less than 84.8, you can use the Central Limit Theorem. The sample mean follows a normal distribution with mean (mu) = 89 and standard deviation (sigma/sqrt(n)) = 22/sqrt(66). You can then standardize the value 84.8 and use the standard normal distribution table or calculator to find the probability.

To find the probability that the sample mean is greater than 886, you can use the same approach. Standardize the value 886 and use the standard normal distribution table or calculator to find the probability.