Final answer:
To calculate the electric field in a parallel-plate capacitor with a dielectric, divide the surface charge density by the product of the permittivity of free space and the dielectric constant. If the charge and the dielectric constant are known, the electric field can be found.
Step-by-step explanation:
The student is asking about the electric field inside a parallel-plate capacitor filled with a dielectric material. The electric field (E) in a parallel-plate capacitor without a dielectric is given by E = σ/ε0, where σ represents the surface charge density (σ = Q/A), and ε0 is the permittivity of free space. When a dielectric with a dielectric constant K is inserted between the plates, the electric field is reduced by a factor of K, so the new electric field is E' = E/K = σ/(ε0K).
In this specific student's question, the charge Q on each plate is given as 9.00 μC and the dielectric constant K is 5. To calculate the electric field in the dielectric, first determine the surface charge density: σ = Q/A. With A being the area of the plates and ε0 = 8.85 × 10^{-12} F/m, the electric field in the dielectric can then be computed using E' = σ/(ε0K).