Question

A nonconducting sphere has radius R=1.79 cm and uniformly distributed charge q=+1.70fC. Take the electric potential at the sphere's center to be V0 =0. What is V at radial distance from the center (a) r=0.820 cm and (b) r=R ? (Hint: See Module 23.6.) (a) Number Units (b) Number Units

Answer 1

To find the electric potential at a certain radial distance from the center of a nonconducting sphere, you can use the formula V = k*q/r, where V is the electric potential, k is the Coulomb constant, q is the charge, and r is the radial distance. Using this formula, we can calculate the electric potential for given values of radial distance and charge.

Step-by-step explanation:

To find the electric potential at a radial distance from the center of a nonconducting sphere, we use the formula V = k*q/r, where V is the electric potential, k is the Coulomb constant, q is the charge, and r is the radial distance. Given that the sphere's radius R=1.79 cm and charge q=+1.70fC, we can calculate V for (a) r=0.820 cm and (b) r=R.

(a) For r=0.820 cm, the electric potential V is:

V = (8.99e9 N*m²/C²)*(1.70e-15 C)/(0.820e-2 m) = 1.88 V

(b) For r=R, the electric potential V is:

V = (8.99e9 N*m²/C²)*(1.70e-15 C)/(1.79e-2 m) = 1.36 V