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The Schwarzschild radius of a black hole containing 7.05×10 ²⁸ kg is meters. Only enter your numerical answer below - do not include units.

User Iivannov
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Final answer:

The Schwarzschild radius of the black hole is approximately \(1.047 \times 10^5\).

Step-by-step explanation:

The Schwarzschild radius (\(r_s\)) of a black hole can be calculated using the formula:

\[ r_s = \frac{2G M}{c^2} \]

where:

\( G \) is the gravitational constant (\(6.67 \times 10^{-11} \, \text{m}^3 \, \text{kg}^{-1} \, \text{s}^{-2}\)),

\( M \) is the mass of the black hole (given as \(7.05 \times 10^{28} \, \text{kg}\)),

\( c \) is the speed of light in a vacuum (\(3.00 \times 10^8 \, \text{m/s}\)).

Now, plug in the values and calculate:

\[ r_s = \frac{2 \times 6.67 \times 10^{-11} \times 7.05 \times 10^{28}}{(3.00 \times 10^8)^2} \]

\[ r_s \approx 1.047 \times 10^5 \]

The Schwarzschild radius of the black hole is approximately \(1.047 \times 10^5\).

User Mohamed Gaber
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