Question

Assume that mütary aircraft use ejection seats designed for men weighing between 135.2 lb and 220 lb. If women's weights are distributed with a mean Of 178.3 lb and a standard deviation Of 49.3 L, what percentage of women have weights that are within those hits? Many women excluded With those specifications?

Answer 1

To determine the percentage of women with weights within the specified range, calculate the z-scores for the lower and upper limits of the weight range and find the difference between the cumulative probabilities.

Step-by-step explanation:

To determine the percentage of women with weights within the specified range, we will use the concept of standard deviation. First, we need to calculate the z-scores for the lower and upper limits of the weight range. The z-score is calculated by subtracting the mean from the weight and dividing by the standard deviation. For the lower limit, the z-score is (-220 - 178.3) / 49.3 = -1.13, and for the upper limit, the z-score is (-135.2 - 178.3) / 49.3 = -0.873. We can then use a standard normal distribution table or a calculator to find the cumulative probability associated with these z-scores. The percentage of women with weights within those limits is the difference between the cumulative probabilities.