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Determine the sample size n needed to construct a 99% confidence interval to estimate the population mean for the following margins of error when σ=79

. a) 10
b) 15
c) 2

User Ding Peng
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Final answer:

To determine the sample size needed to construct a 99% confidence interval to estimate the population mean, use the formula n = (z^2 * σ^2) / EBM^2, where n is the sample size, z is the z-value, σ is the population standard deviation, and EBM is the margin of error.

Step-by-step explanation:

To determine the sample size needed to construct a 99% confidence interval to estimate the population mean, we can use the formula:

n = (z^2 * σ^2) / EBM^2

where n is the sample size, z is the z-value corresponding to the desired confidence level, σ is the population standard deviation, and EBM is the desired margin of error. In this case, σ = 79.

a) For a margin of error of 10:

n = (1.96^2 * 79^2) / 10^2 = 286.55

Rounding up to the next higher integer, the sample size needed is 287.

b) For a margin of error of 15:

n = (1.96^2 * 79^2) / 15^2 = 101.33

Rounding up to the next higher integer, the sample size needed is 102.

c) For a margin of error of 2:

n = (1.96^2 * 79^2) / 2^2 = 1203.52

Rounding up to the next higher integer, the sample size needed is 1204.

User Tommy Leong
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