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How many distinct real solutions does the below equation have?
x⁴-5 x²+6=0

1 Answer

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Final answer:

The given equation x² + 0.0211x - 0.0211 = 0 has 0 distinct real solutions.

Step-by-step explanation:

The given equation is a quadratic equation in the form ax²+bx+c = 0, where a = 1, b = 0, and c = 0.0211. To find the number of distinct real solutions, we can use the discriminant, which is given by the formula: Δ = b² - 4ac. Substituting the values, we get: Δ = (0)² - 4(1)(0.0211) = -0.0844.

Since the discriminant is negative, the quadratic equation has no real solutions. Therefore, the given equation x² + 0.0211x - 0.0211 = 0 has 0 distinct real solutions.

User Jnorris
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