89.4k views
5 votes
Two regular pentagons have areas of 20 mm^(2) and x^(2) - x mm^(2.) What values of x make the pentagons congruent?

User Ekholm
by
8.3k points

1 Answer

4 votes

Final answer:

To determine the values of x that make the pentagons congruent, we need to find the side length of each pentagon and solve an equation involving the areas of the pentagons.

Step-by-step explanation:

To determine the values of x that make the pentagons congruent, we need to find the side length of each pentagon. The area of a regular pentagon can be found using the formula:

A = (5/4) * s^2 * cot(180/5),

where s is the side length. Thus, for the pentagon with an area of 20 mm^2, we have 20 = (5/4) * s^2 * cot(36).

Solving for s, we find s = sqrt((80 * cot(36))/5).

Next, we substitute this value of s into the expression for the area of the second pentagon, x^2 - x, and solve for x.

Setting the expressions for the areas of both pentagons equal to each other, we have

(5/4) * s^2 * cot(36) = x^2 - x.

Solving this equation yields the values of x that make the pentagons congruent.

User Igor Berman
by
8.9k points