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Two of the sides of a rectangle have a length of 3 units. The points (-1,2) and (6,2) are adjacent vertices of a rectangle. To the nearest tenth, what is the length of a diagonal of the rectangle? (Hint: Use sraph paper ) a. 7.6 units b. 6.3 units c. 3.8 units d. 32 units

User Akhikhl
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Final answer:

Using the Pythagorean theorem, the length of the diagonal of the rectangle with adjacent vertices (-1,2) and (6,2) and side lengths of 3 units is approximately 7.6 units.

Step-by-step explanation:

To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem which states that in a right triangle, the sum of the squares of the two sides is equal to the square of the hypotenuse. The given points (-1,2) and (6,2) are adjacent vertices of a rectangle, and they form one side of the rectangle. Since both these points have the same y-coordinate, this side is horizontal, and its length can be calculated by taking the difference of the x-coordinates: 6 - (-1) = 7 units.

Since two sides of the rectangle have a length of 3 units, and these represent the shorter sides of the rectangle, we can form a right triangle where one side is 3 units (the width), another side is 7 units (the length), and the diagonal of the rectangle is the hypotenuse. Applying the Pythagorean theorem:

√(3 units)² + (7 units)² = √(9 units² + 49 units²) = √58 units²

To the nearest tenth, the diagonal is approximately:

√58 units² ≈ 7.6 units

Therefore, the answer to the length of the diagonal of the rectangle is 7.6 units.

User Marik Ishtar
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