Question

Consider an intrinsic piece of semiconductor with n, = 10¹⁰ cm⁻³ electron mobility uₑ=

1000cm²/V.s, mobility uₕ =1cm²/V.s
a) Calculate the resistivity of the semiconductor
b) Calculate the resistance of a wire made of this material, with length L=10 mm and
cross section area A= 1 mm²?

Answer 1

The resistivity of a semiconductor can be calculated using the carrier concentration and the mobilities of electrons and holes, while the resistance of a wire is found using the resistivity, the wire's length, and cross-sectional area.

Step-by-step explanation:

Calculating the Resistivity and Resistance of a Semiconductor

To find the resistivity of the semiconductor, we use the intrinsic carrier concentration (ni) and the mobilities of the electrons (ue) and holes (uh). The resistivity p is given by 1 / (q * ni * (ue + uh)), where q is the charge of an electron (1.60×10-19 C). Plugging in the values, we calculate the resistivity.

To calculate the resistance R of a wire made of this semiconductor with length L = 10 mm and cross-sectional area A = 1 mm², we use the formula R = pL / A. By substituting the calculated resistivity and the given dimensions, we obtain the resistance of the wire.