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A typical helicopter with four blades rotates at 260 rpm and has a kinetic energy of 5.45 x 10⁵. What is the total moment of inerta, in kg.m² of the blades?

_______________ka.m².

User StephanT
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1 Answer

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The moment of inertia of the blades is 66.7 kg.m^2.

The moment of inertia of the blades can be calculated using the formula:

Moment of Inertia = (1/3) * m * r^2

where m is the mass of each blade and r is the distance from the axis of rotation to the tip of the blade.

Given that each blade has a mass of 50.0 kg and a length of 4.00 m, the distance from the axis of rotation to the tip of the blade is half of its length, which is 2.00 m.

Substituting the values into the formula, we get:

Moment of Inertia = (1/3) * 50.0 kg * (2.00 m)^2

Moment of Inertia = (1/3) * 50.0 kg * 4.00 m^2

Moment of Inertia = 66.7 kg.m^2

User Kuru
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