Question

The red box has a mass of 23.9 kg and the blue box has a mass of 6.2 kg and the force is 284 N. To the nearest tenth of a m/s²

what is the acceleration of the combination? To the nearest newton in problem 5 what force does the blue box exert on the red box? wagon? To the nearest newton what would be the minimum force applied at that angle which would lift the wagon off the ground? A student stands on a scale in an elevator that is accelerating at −2 m/s² . If the student has a mass of 91 kg, to the nearest newton what is the scale reading? A 24 kg child sits on a 5 kg sled and slides down a 85 meter, 31 degree slope, to the nearest m/s what is his or her speed at the bottom?

Answer 1

The acceleration of the combination of the boxes is 9.4 m/s². The force exerted by the blue box on the red box is 284 N. The minimum force required to lift the wagon off the ground depends on its weight.

Step-by-step explanation:

To find the acceleration of the combination of the red and blue boxes, we can use Newton's second law of motion, which states that force is equal to mass times acceleration (F=ma).

In this case, the force is 284 N and the combined mass of the boxes is 23.9 kg + 6.2 kg = 30.1 kg. Therefore, the acceleration is a = F/m = 284 N / 30.1 kg = 9.4 m/s² (rounded to the nearest tenth).

To find the force exerted by the blue box on the red box, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. Since the blue box pushes against the red box with a force of 284 N, the red box will push back with an equal force of 284 N.

To find the minimum force applied at an angle which would lift the wagon off the ground, we need to consider the force components. Let's assume the angle is θ. The vertical component of the force (Fv) should be equal to the weight of the wagon. Therefore, Fv = mg, where m is the mass of the wagon and g is the acceleration due to gravity.