Final answer:
To prepare the 9 PCR reactions, volumes of each component are calculated based on the desired final concentration for a 50 µl reaction volume.
Step-by-step explanation:
To set up 9 PCR reactions with the final volume of 50 µl, we first need to calculate the volume of each component required per reaction based on the final concentration and then multiply by 9 for all reactions.
5X Reaction Buffer: To get to 1.0X from a 5X stock, you need 1/5th of the final volume which is 10 µl per reaction. So for 9 reactions, it's 90 µl.
MgCl2: To get 1.5 mM from 25 mM, the dilution factor is 25/1.5. So we need 50 µl/ (25/1.5) = 3 µl per reaction. For 9 reactions, it's 27 µl.
Nucleotide Mix: To get 0.2 mM from 20 mM, the dilution factor is 20/0.2. So we need 50 µl / (20/0.2) = 0.5 µl per reaction. For 9 reactions, that's 4.5 µl.
Primers: For 1 µM from a 10 µM stock, use 5 µl. So, 5 µl each of Primer 1 and Primer 2, which results in a total of 90 µl for each primer over all reactions.
Taq DNA Polymerase: For 1 Unit from 5 Units/µl, we need 0.2 µl per reaction, resulting in 1.8 µl for 9 reactions.
1 µl of Template DNA is added directly to each reaction.
The rest of the volume to 50 µl will be made up with distilled water for each PCR reaction.
Quantity of Primers in pmol
To calculate the number of pmol of each primer in each reaction: since 1 µl of 1 µM primer solution contains 1 pmol of primer, we will use 1 µl of each primer, so we will have 1 pmol of each primer in each reaction.