Question

The specific weight of a fluid is 112XY N/m3. Calculate the mass contained in 2 m3

(a) Using the maximum gravity on the earth’s surface.
(b) Using the minimum gravity on the earth’s surface.

Answer 1

The mass of the fluid for a specific weight of 112XY N/m³ in a 2 m³ volume can be calculated by dividing the weight of the fluid by the acceleration due to gravity, considering both maximum and minimum gravity values on Earth's surface.

Step-by-step explanation:

The specific weight (also known as weight density) of a fluid is given as 112XY N/m3. To calculate the mass contained in a volume of fluid, we use the formula for specific weight γ = weight γ / volume V. Hence, the mass m can be determined by dividing the weight by the acceleration due to gravity g (m = γ / g).

To address both parts of the question:

1. (a) Using the maximum gravity on Earth's surface, which is approximately 9.81 m/s2.
2. (b) Using the minimum gravity on Earth's surface, which is approximately 9.78 m/s2.

This implies the following:

1. (a) For maximum gravity, m = (112XY N/m3) × (2 m3) / 9.81 m/s2
2. (b) For minimum gravity, m = (112XY N/m3) × (2 m3) / 9.78 m/s2

These equations will provide the mass of the fluid in kilograms for the given volume under different gravitational conditions.