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Two small objects, A and B, are fixed in place and separated by 2.64 cm in a vacuum. Object A has a charge of +1.29μC, and object B has a charge of −1.29μC. How many electrons must be removed from A and put onto B to make the electrostatic force that acts on each object an attractive force whose magnitude is 37.7 N ?

User MaxouMask
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To modify the electrostatic force between two objects to a desired attraction, one must calculate the number of electrons to be moved based on Coulomb's law and the charge of an electron. The provided answer indicates the specific number of electrons that need to be transferred.

To make the electrostatic force between two charged objects an attractive force with a magnitude of 37.7 N, it is necessary to calculate the number of electrons to be transferred from object A to object B. By applying Coulomb's law, we can first find the initial force between the objects using their given charges (+1.29μC and -1.29μC) and the separation of 2.64 cm, and then determine the amount of charge transfer needed to achieve the desired force.

To get an attractive force of 37.7 N, we arrange the known quantities in Coulomb's law formula and solve for the charge. Since electrons have a charge of approximately -1.6 x 10-19 C, we divide the needed charge difference by the charge of one electron to find the number of electrons to be moved. The final answer, provided in the response, will represent the number of electrons required for this transfer.

In conclusion, to alter the force between two charged objects, charges can be transferred from one object to another. This is a standard electrostatics problem involving the manipulation of charge to achieve a specific inter-object force.

User AvMishra
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