Final answer:
The magnetic field at a distance of 8 cm from the wire carrying a 1 A current is 0.512 μT.
Step-by-step explanation:
To determine the magnetic field at a distance of 8 cm from the wire, we can use the inverse square law. The magnetic field is inversely proportional to the square of the distance from the wire. So, if the magnetic field is 2 μT at a distance of 10 cm, we can calculate the magnetic field at a distance of 8 cm using the formula:
B1/B2 = (d2^2)/(d1^2)
Let B2 be the magnetic field at 8 cm and B1 be the magnetic field at 10 cm. Plugging in the values, we get:
B2/ (2 μT) = (8 cm)^2 / (10 cm)^2
B2 = (8 cm)^2 / (10 cm)^2 * 2 μT
Simplifying the equation, we get:
B2 = 0.512 μT