The box with a mass of 3.00 kg sliding down a 26.5-degree incline accelerates at 1.90 m/s² when covering a distance of 2.00 m in 1.45 seconds from rest.
To find the magnitude of the acceleration of the box sliding down an incline, we can use the formula s = ut + (1/2)at², where s is the distance traveled, u is the initial velocity, a is the acceleration, and t is the time. Since the box starts from rest, u = 0. Plugging the values in, we get 2.00 m = (1/2) * a * (1.45 s)². Solving for a gives us the acceleration of the box.
Final answer in 2 lines: The acceleration of the box is calculated as a = (2 * s) / t², which gives a = (2 * 2.00 m) / (1.45 s)² = 1.90 m/s².
Conclusion: The box accelerates down the incline with an acceleration of 1.90 m/s².