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An electron has a velocity of 1.75E+4m/s (in the positive x direction) and an acceleration of 1.89E+12 m/s2 (in the positive z direction) in uniform electric and magnetic fields. If the electric field has a magnitude of 19.3N/C (in the positive z direction), what is the y component of the magnetic field in the region?

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The y component of the magnetic field in the region is negative.

The electron has a velocity of 1.75E+4 m/s in the positive x direction and an acceleration of 1.89E+12 m/s2 in the positive z direction in uniform electric and magnetic fields. The magnitude of the electric field is given as 19.3 N/C in the positive z direction. We need to find the y component of the magnetic field in the region.

To find the y component of the magnetic field, we can use the Lorentz force equation which states that the magnetic force on a charged particle is given by Fmagnetic = q(v x B), where q is the charge of the particle, v is the velocity, and B is the magnetic field. In this case, the electric field does not affect the magnetic force, so we can ignore it. Since the magnetic force is in the positive z direction and the velocity is in the positive x direction, the magnetic field must be in the negative y direction. Hence, the y component of the magnetic field is negative.

Therefore, the y component of the magnetic field in the region is negative.

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