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A uniform maqnetic field of magnitude 0.70 T is directed perpendicular to the plane of a rectangular loop having dimensions 7.9 cm by 11 cm. Find the magnetic flux through the loop.

User Imdahmd
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Final answer:

To calculate the magnetic flux, multiply the magnetic field's magnitude (0.70 T) by the area of the loop in meters squared (0.00869 m²) because the field is perpendicular to the loop's plane. The magnetic flux through the loop is 6.083 × 10⁻³ webers (Wb).

Step-by-step explanation:

The magnetic flux through a loop is found using the formula Φ = B × A × cos(θ), where Φ is the magnetic flux, B is the magnitude of the magnetic field, A is the area of the loop, and θ is the angle between the magnetic field lines and the normal (perpendicular) to the loop's surface. In this case, the magnetic field is perpendicular to the loop's plane (θ = 0 degrees), so cos(θ) = cos(0) = 1. First, convert the dimensions of the loop to meters (7.9 cm = 0.079 m and 11 cm = 0.11 m). Then, calculate the area A = length × width = 0.079 m × 0.11 m = 0.00869 m².

Now, you can calculate the magnetic flux: Φ = 0.70 T × 0.00869 m² × 1 = 0.006083 T·m² or 6.083 × 10⁻³ Wb (webers).

User Peter Gaultney
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