Question

In New England, the horizontal component of the Earth's magnetic field has a magnitude of 2.3×10⁻⁵ T. An electron is shot vertically straight up from the ground with a speed of 3.9×10⁶ m/s. What is the magnitude of the acceleration caused by the magnetic force?

Answer 1

The magnitude of the acceleration caused by the magnetic force is 1.474x10^-17 N.

Step-by-step explanation:

The magnitude of the acceleration caused by the magnetic force can be found using the formula F = qvB, where F is the force, q is the charge, v is the velocity, and B is the magnetic field. In this case, the electron has a charge of -1.6x10^-19 C and a velocity of 3.9x10^6 m/s. The magnitude of the Earth's magnetic field in New England is given as 2.3x10^-5 T. Plugging the values into the formula, we get:

F = (-1.6x10^-19 C)(3.9x10^6 m/s)(2.3x10^-5 T) = -1.474x10^-17 N

Therefore, the magnitude of the acceleration caused by the magnetic force is 1.474x10^-17 N.