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A cylinder of pure gold is 0.75 cm in diameter and 0.5 m long. What is the resistance of this gold "wire" from one end to the other?

User Slwr
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1 Answer

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Final answer:

To find the resistance of a cylindrical wire, we can use the formula R = (ρ * L) / (A), where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area of the wire. In this case, the wire is made of gold, so we need to use the resistivity value of gold and calculate the cross-sectional area using the given diameter. Once we have the cross-sectional area, we can plug in the values and calculate the resistance of the gold wire.

Step-by-step explanation:

To calculate the resistance of a cylindrical wire, we need to use the formula:

R = (ρ * L) / (A)

Where:

  • R is the resistance of the wire
  • ρ (rho) is the resistivity of the material
  • L is the length of the wire
  • A is the cross-sectional area of the wire

In this case, the wire is made of gold. The resistivity of gold is ρ = 2.44 × 10^-8 Ω.m.

The length of the wire is L = 0.5 m.

The diameter of the wire is given as 0.75 cm, so we need to calculate the cross-sectional area using the formula:

A = π * (d/2)^2

Where:

  • d is the diameter of the wire

Once we have the cross-sectional area, we can substitute the values into the resistance formula to find the resistance of the gold wire.

Remember to convert the diameter to meters before calculating the cross-sectional area.

User Tiki
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