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What is the orbital period (in s) of a bit of matter in an accretion disk that is located 6 ✕ 10⁵ km from a 38 M black hole?

Hint: Use the circular orbit velocity formula,Vc = GM/r
What is the ratio of the percent of metals in intermediate Population I stars (1.5%) to that in extreme Population II stars (0.05%)?

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Final answer:

The orbital period of matter in an accretion disk depends on the mass of the black hole and the radius of the orbit, which requires additional context to answer properly. The ratio of metallicity between intermediate Population I stars and extreme Population II stars is 30.

Step-by-step explanation:

The question pertains to the calculation of the orbital period of matter in an accretion disk and the ratio of metallicity between different populations of stars.

To find the orbital period (T) of a bit of matter in an accretion disk around a black hole, we would use the formula for circular orbit velocity (Vc = √(GM/r)) and then use (T=2πr/Vc) to find the period. However, this specific question cannot be accurately answered without additional relevant information or context being provided. It's also important to note that the variables in the orbital velocity formula include: G (the gravitational constant), M (the mass of the black hole), and r (the radius of the orbit).

The ratio of the percent of metals in intermediate Population I stars versus that in extreme Population II stars can be calculated by dividing the two percentages. In the given example, this ratio is 1.5%/0.05% which equals 30.

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