Question

An ideal transformer has 4500. turns in its primary (input) and

14500. turns in its secondary (output). 10.0-V ac is connected to
the primary (input). a) What is the voltage on the secondary
(output)?

Answer 1

Using the transformer equation, the secondary voltage of the transformer with 4500 turns in the primary and 14500 turns in the secondary, with a 10.0 V primary voltage, is calculated to be 32.22 V.

Step-by-step explanation:

To determine the voltage on the secondary (output) of an ideal transformer, we use the transformer equation which relates the primary and secondary voltages with the number of turns on the primary (Np) and secondary (Ns) coils:

Vp/Vs = Np/Ns

In your case, the primary voltage (Vp) is 10.0 V, the number of primary turns (Np) is 4500, and the number of secondary turns (Ns) is 14500. We can plug these values into the equation to find the secondary voltage (Vs).

Substituting the given values:

10.0 V / Vs = 4500 turns / 14500 turns

Vs = (14500 turns / 4500 turns) * 10.0 V

Vs = 3.222... * 10.0 V

Vs = 32.22 V