Question

An isolated conducting sphere has a 10cm radius. One wire carries a current of 1.0000020Ainto it. Another wire carries a current of 1.0000000 A out of it. How long would it take for the sphere to increase in potential by 1000 V?

Answer 1

The time it would take for the isolated conducting sphere to increase in potential by 1000 V is 1000 seconds.

Step-by-step explanation:

In order to find the time it takes for the potential of the conducting sphere to increase by 1000 V, we need to use the concept of charge conservation.

Charge conservation:

Since the net charge on the sphere remains constant, the total current entering the sphere must be equal to the total current leaving the sphere.

Formula:

Current = Charge / Time

Applying this formula to the given situation:

Time = Charge / Current

Time = (1000 V)/(1.0000020 A - 1.0000000 A)

Time = 1000 seconds