Question

A 1300 kg car is traveling at 27 m/s. The driver hits the breaks and brings the car to a stop in 3.8 s. [10 points] a. What was the initial kinetic energy of the car? [ 3 points ] b. What was the net work done to stop the car?

Answer 1

The initial kinetic energy of the car is 526,950 joules, and the net work done to stop the car is also 526,950 joules.

Step-by-step explanation:

To find the initial kinetic energy of the car, we can use the equation:

Ek = 0.5 * m * v2

where Ek is the kinetic energy, m is the mass of the car, and v is the velocity of the car.

Plugging in the given values:

Ek = 0.5 * 1300 kg * (27 m/s)2 = 526,950 J

Therefore, the initial kinetic energy of the car is 526,950 joules.

For part b, the net work done to stop the car is equal to the initial kinetic energy of the car. So the net work done is also 526,950 joules.