Question

If package A has a basic rental payment of RM40 and an extra payment of RM8 for every rental hour, and package B has no basic rental payment but RM15 for every rental hour, what is the maximum time, in hours, of the rental such that package B will be cheaper than package A?

A) 2 hours
B) 3 hours
C) 4 hours
D) 5 hours

Answer 1

By setting up and solving an inequality, we discover that package B is cheaper than package A for a maximum rental time of 5 hours. After that, package A becomes the more cost-effective option.

Step-by-step explanation:

To determine the maximum time of the rental for which package B will be cheaper than package A, we need to set up an inequality. Let x be the number of rental hours.

Package A's cost is represented by the equation: Cost_A = 40 + 8x

Package B's cost is represented by the equation: Cost_B = 15x

To find out when package B is cheaper, we need to find when Cost_B is less than Cost_A:

15x < 40 + 8x

Subtract 8x from both sides:

7x < 40

Divide both sides by 7 to get x:

x < 40 / 7

Dividing 40 by 7 yields approximately 5.71. Since we cannot rent for a fraction of an hour, we round down to the nearest whole hour:

x < 5.71 becomes x <= 5

Therefore, the maximum time of the rental for which package B will be cheaper than package A is 5 hours (Option D).