Question

A massless spring hangs from the ceiling with a small object attached to its lower end. The object is initially held at rest in a position y, such that the spring is at its rest length. The object is then released from y; and oscillates up and down, with its lowest position being 22 cm below yᵢ.

What is the frequency of the oscillation?

Answer 1

To calculate the frequency of the oscillation, use the formula: f = (1 / (2π)) * sqrt(k / m), where k is the force constant of the spring and m is the mass of the object. Determine the amplitude of the oscillation by finding the distance between the initial position and the lowest position. Substitute the values into the formula to find the frequency.

Step-by-step explanation:

The frequency of an oscillation is determined by the formula:

f = (1 / (2π)) * sqrt(k / m)

Where:

• f is the frequency
• k is the force constant of the spring
• m is the mass of the object

In this case, the object is initially held at rest in a position y and is released to oscillate up and down.

Given that the lowest position is 22 cm below y, we can determine the amplitude of the oscillation (A) as the distance between y and the lowest position (A = y - 22 cm).

By using the formula for the frequency, we can calculate it by substituting the known values of the force constant and the mass.