Question

Three resistors having resistances of R1= 1.66 , R2 = 2.50 and R3 = 4.71 respectively, are connected in series to a 28.3V battery that has negligible internal resistance.Find the equivalent resistance.

Answer 1

The equivalent resistance of the three resistors in series is 8.87Ω.

Step-by-step explanation:

To find the equivalent resistance of three resistors connected in series, you simply add their resistance values together. Given the resistances R1= 1.66Ω, R2 = 2.50Ω, and R3 = 4.71Ω, the equivalent resistance would be:

Req = R1 + R2 + R3

So, the equivalent resistance is:

Req = 1.66Ω + 2.50Ω + 4.71Ω = 8.87Ω

Thus, the equivalent resistance of the circuit consisting of the given three resistors in series is 8.87Ω.