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A wedding ring is tossed into the air and given a spin, resulting in an angular velocity of 16.1 rotations per second. The rotation axis is a diameter of the ring. The magnitude of the Earth’s magnetic field is 3.89·10–5 T at this location. If the maximum induced voltage in the ring is 1.175×10-6 V, what is the diameter of the ring?

User Tmslnz
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Final answer:

This physics question requires using Faraday's law of induction to calculate the diameter of a wedding ring based on the induced voltage and the known values of the ring's angular velocity and the Earth's magnetic field.

Step-by-step explanation:

The question presented involves concepts from physics, in particular, the relationship between the induced voltage in a conductive loop—here a wedding ring—and the magnetic field it is exposed to. We are given the angular velocity of the ring, the magnitude of the Earth’s magnetic field at the location, and the maximum induced voltage in the ring. We are asked to find the diameter of the ring. Using Faraday's law of induction and considering the area swept by the wedding ring during its rotation, we can solve for the diameter of the ring.

User Andre Gallo
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