Question

A 31.0-cm long solenoid 1.25 cm in diameter is to produce a

field of 4.60 mT at its center.
How much current should the solenoid carry if it has 950 turns
of the wire?

Answer 1

To calculate the current required for a solenoid to produce a given magnetic field, we can use the formula B = (μ₀ * n * I), where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current. Plugging in the given values, the current required for the solenoid is determined to be...

Step-by-step explanation:

To calculate the current required for a solenoid to produce a magnetic field, we can use the formula:

B = (μ₀ * n * I)

Where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current.

Plugging in the given values, we have:

4.60 mT = (μ₀ * 950 * I)

Simplifying further:

I = 4.60 mT / (μ₀ * 950)

From here, we can substitute the value of μ₀ (permeability of free space) which is 4π × 10⁻⁷ T m/A. Plugging in this value and evaluating the expression, we can find the current required for the solenoid.