Question

The electric field of a radio wave travelling through vacuum has amplitude Emax = 3 × 10−4 V/m and frequency fE = 1.40 MHz. What is the frequency of the corresponding magnetic field in MHz?

Answer 1

The frequency of the corresponding magnetic field in MHz is approximately 1.40 MHz.

Step-by-step explanation:

The frequency of an electromagnetic wave is related to the speed of light in a vacuum. The formula for the relationship is:

c = λf

Where c is the speed of light, λ is the wavelength, and f is the frequency.

Given the frequency of the electric field, fE = 1.40 MHz, we can calculate the wavelength using the formula:

λ = c / fE

Assuming the speed of light in a vacuum is approximately 3.00 x 10^8 m/s, we can substitute the values into the formula and solve for the wavelength:

λ = (3.00 x 10^8 m/s) / (1.40 x 10^6 Hz)

λ = 2.14 x 10^2 m

Now, to find the frequency of the corresponding magnetic field, we can use the wavelength and the formula:

fB = c / λ

Substituting the values into the formula:

fB = (3.00 x 10^8 m/s) / (2.14 x 10^2 m)

fB ≈ 1.40 x 10^6 Hz

Therefore, the frequency of the corresponding magnetic field is approximately 1.40 MHz.