Question

A horizontal power line carries a current of 6110 A from south to north. Earth's magnetic field (78.4μT) is directed toward the north and is inclined downward at 62.0∘ to the horizontal. Find the (a) magnitude and (b) direction of the magnetic force on 150 m of the line due to Earth's field. (a) Number Units

Answer 1

The magnitude of the magnetic force on the wire is 0.5 N.

Step-by-step explanation:

The magnitude of the magnetic force on the power line can be determined using the formula:

F = I * B * L * sin(theta)

where I is the current, B is the magnetic field, L is the length of the wire, and theta is the angle between the current and magnetic field.

In this case, the current is 1000 A, the magnetic field is 5.00 x 10-5 T, the length of the wire is 100 m, and the angle is 30.0°. Plugging these values into the formula, we get:

F = (1000 A) * (5.00 x 10-5 T) * (100 m) * sin(30.0°)

Simplifying the equation gives us:

F = 0.5 N

Therefore, the magnitude of the force on the wire is 0.5 N.