57.2k views
5 votes
Complete the Punnett square. Heterozygous red-eyed female Drosophila are crossed with white-eyed males. What are the eye colors of each possible genotype that would occur in the F1? What ratio of genotype and phenotype would be expected in this cross?

User Sangupta
by
7.6k points

1 Answer

4 votes

Final answer:

The possible genotypes in the F1 generation would be heterozygous red-eyed females (XWXw) and white-eyed males (XWY). The ratio of genotype and phenotype in the F1 generation would be 1:1.

Step-by-step explanation:

In this cross, a white-eyed male fruit fly is crossed with a heterozygous red-eyed female fruit fly. The Punnett square is used to determine the possible genotypes and eye colors of the offspring. The Punnett square would show that there is a 50% chance of producing red-eyed females and a 50% chance of producing white-eyed males in the F1 generation. Therefore, the possible genotypes and eye colors in the F1 generation would be:

1. Heterozygous red-eyed females (XWXw)

2. White-eyed males (XWY)

The ratio of genotype in the F1 generation would be 1:1, meaning equal numbers of heterozygous red-eyed females and white-eyed males. The ratio of phenotype would also be 1:1 since the red-eyed phenotype is dominant over the white-eyed phenotype.

User Stefan Dollase
by
7.0k points