220k views
0 votes
Please help need answer now

Please help need answer now-example-1
User Danijel
by
7.8k points

2 Answers

2 votes
The slope of AB is (-1–5)/(12-2) = -3/5.
To find the perpendicular bisector, take the negative reciprocal of the slope. The negative reciprocal of -3/5 is 5/3, so the answer is 5/3.
2 votes

Answer:


\sf (5)/(3)

Explanation:

The slope of the perpendicular bisector of a line segment
\sf \overline{AB} is the negative reciprocal of the slope of the line segment
\sf \overline{AB}.

The slope of a line passing through two points
\sf (x_1, y_1) and
\sf (x_2, y_2) is given by:


\sf m = (y_2 - y_1)/(x_2 - x_1)

For the line segment
\sf \overline{AB}, with points
\sf A(2,5) and
\sf B(12,-1):


\sf m_(AB) = (-1 - 5)/(12 - 2)


\sf m_(AB) = (-6)/(10)


\sf m_(AB) = -(3)/(5)

The negative reciprocal of
\sf -(3)/(5) is
\sf (5)/(3).

Therefore, the slope of the perpendicular bisector of
\sf \overline{AB} is
\sf (5)/(3).

User Radulle
by
8.5k points