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Given: 2Al + 6HCl --> 2 AlCl3 + 3H2.

You reacted 43.50ml of 6M HCl with 2.25g of Aluminum and collected the hydrogen above water. What is the total pressure if the volume collected was 2.00 quarts at 63.0F? Water vapor pressure at 63.0F is 23.8 torr.

a) 153.2 torr
b) 181.0 torr
c) 185.8 torr
d) 238.8 torr

User Shinnok
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1 Answer

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Final answer:

To find the total pressure, calculate the moles of HCl reacted, use stoichiometry to determine the moles of hydrogen gas produced, apply the ideal gas law for hydrogen, and add the water vapor pressure.

Step-by-step explanation:

The question asks for the total pressure in a container after reacting aluminum with hydrochloric acid and measuring the volume of hydrogen gas collected. The student is given the balanced chemical equation 2Al + 6HCl → 2AlCl3 + 3H2 and a set of conditions (volume of HCl, concentration of HCl, mass of aluminum, volume of gas collected, temperature, and vapor pressure of water) to use in order to calculate the total pressure of the collected hydrogen gas plus the water vapor pressure.

The student will first need to calculate the number of moles of HCl reacted using the molarity and volume of HCl solution, and then use the stoichiometry of the reaction to find the theoretical moles of hydrogen gas produced. Afterward, the student will apply the ideal gas law to find the partial pressure of hydrogen gas at the given temperature and volume (converted to liters and Kelvin, respectively). The total pressure in the container will then be the sum of the partial pressure of hydrogen gas and the water vapor pressure at 63 degrees Fahrenheit.

User Pawelbial
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