Question

A 23.3 g sample of metal X requires 126 calories of energy to heat it from 10.0°C to 82.0°C. Calculate the specific heat of metal X.

A) 0.54 J/g ·°C
B) 1.20 J/g ·°C
C) 4.14 J/g ·°C
D) 7.58 J/g ·°C

Answer 1

The specific heat of A 23.3 g sample of metal X requires 126 calories of energy to heat it from 10.0°C to 82.0°C is approximately 0.54 J/g ·°C (Option A).

Step-by-step explanation:

The specific heat of a substance is a measure of how much heat energy is required to raise the temperature of 1 gram of the substance by 1 degree Celsius. To calculate the specific heat of metal X, we can use the formula:

specific heat = heat energy / (mass * change in temperature)

Given that a 23.3 g sample of metal X requires 126 calories (1 calorie = 4.18 joules) to heat it from 10.0°C to 82.0°C, we can calculate the specific heat as:

specific heat = 126 calories / (23.3 g * (82.0°C - 10.0°C))

= 0.54 J/g ·°C.

Thus, the correct option is A.