Final answer:
The dragster's average acceleration is 46.034 m/s², the average force on the dragster is 42678.072 N, and the force on the driver is approximately 3262.6106 N.
Step-by-step explanation:
Finding Average Acceleration, Force, and Force Exerted on the Driver
The question asks for the average acceleration of a dragster with mass 926.8 kg that goes from rest to a speed of 26.7 m/s in 0.58 seconds. To calculate the average acceleration (a), we use the formula a = (v - u) / t, where v is the final velocity, u is the initial velocity (which is 0 since the dragster starts from rest), and t is the time. Plugging in the values, we get:
a = (26.7 m/s - 0 m/s) / 0.58 s = 46.034 m/s²
For the second part, we use Newton's second law, F = m * a, to find the average force (F). The mass (m) is 926.8 kg and acceleration (a) is 46.034 m/s². Therefore,
F = 926.8 kg * 46.034 m/s² = 42678.072 N.
For the third part of the question, to find the force on the driver, we again use F = m * a, except this time the mass (m) is the driver's mass, which is 70.9 kg. Hence:
F = 70.9 kg * 46.034 m/s² = 3262.6106 N.
The horizontal force that the seat exerts on the driver is therefore approximately 3262.6106 N.