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A parachutist jumps from a plane and free falls. Sometime after falling, his velocity is 25 m/s. How far has the parachutist fallen?

A) 318.75 m
B) 312.5 m
C) 325 m
D) 300 m

User Kamahire
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1 Answer

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Final answer:

The parachutist has fallen approximately 31.36 meters.

Step-by-step explanation:

To calculate the distance fallen by the parachutist, we can use the equation of motion:

d = (1/2)at^2

Where d is the distance fallen, a is the acceleration, and t is the time.

Since the parachutist is in free fall, the acceleration can be taken as gravitational acceleration, which is 9.8 m/s².

From the information provided, we know that the parachutist's velocity is 25 m/s at some point during the fall.

To find the time taken to reach this velocity, we can use the equation:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Assuming the parachutist starts from rest, u is 0.

Plugging in the values:

25 = 0 + 9.8t

Solving for t:

t = 25/9.8 ≈ 2.55 seconds

Now, we can calculate the distance fallen:

d = (1/2)at^2

d = (1/2) * 9.8 * (2.55)^2 ≈ 31.36 meters

Therefore, the parachutist has fallen approximately 31.36 meters.

User Lyrikal
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