Final answer:
A car traveling at 34 ft/sec will take 13.6 seconds to come to rest if decelerating at a rate of 2.5 ft/sec², calculated using the formula for acceleration.
Step-by-step explanation:
To calculate how many seconds will be required for a car traveling at 34 ft/sec to come to rest while decelerating at 2.5 ft/sec2, we can use the formula for acceleration: a = (Vf - Vi) / t. Here, we know that the final velocity Vf is 0 (since the car comes to rest), the initial velocity Vi is 34 ft/sec, and the acceleration a is -2.5 ft/sec2 (negative because it is deceleration). We can rearrange the equation to solve for time t: t = (Vf - Vi) / a.
Plugging the known values into the equation, we get:
t = (0 - 34 ft/sec) / (-2.5 ft/sec2)
t = 34 / 2.5
t = 13.6 seconds
Therefore, it will take the car 13.6 seconds to come to rest.