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A hockey puck is given an initial speed of

29 m/s on a frozen pond. The puck remains
on the ice and slides 114 m before coming to rest. The acceleration of gravity is 9.8m/s². What is the coefficient of friction between the puck and the ice?
A) 0.372
B) 0.213
C) 0.586
D) 0.125

User HoboBen
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1 Answer

4 votes

Final answer:

To find the coefficient of friction, you can use the kinematic equation v² = u² + 2as with the given values to solve for μ. The calculation reveals that the coefficient of friction between the puck and the ice is 0.372.

Step-by-step explanation:

The given problem involves finding the coefficient of friction between a hockey puck and the ice. To determine the coefficient of friction (μ), the work-energy principle or kinematic equations can be used. Here, we will apply the kinematic equation for uniformly accelerated motion:

v² = u² + 2as

Where v is the final velocity (0 m/s, since the puck comes to rest), u is the initial velocity (29 m/s), a is the acceleration (which we will express in terms of μ and g, where g is the acceleration due to gravity, 9.8 m/s²), and s is the displacement (114 m).

After some algebra with the equation and considering that the acceleration is due to kinetic friction, where a = -μ*g, we get:

μ = −(u²/2gs)

Substituting the given values:

μ = −((29 m/s)² / (2 * 9.8 m/s² * 114 m)) = 0.372

Therefore, the correct answer is A) 0.372.

User Arshovon
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